Suggested Problems for Proof Designer

  1. Hypotheses: A⊂B, A⊂C
    Conclusion: A⊂B∩C
  2. Hypotheses: A⊂B
    Conclusion: C \ B⊂C \ A
  3. Hypotheses: A \ B⊂C
    Conclusion: A \ C⊂B
  4. Hypotheses: none
    Conclusion: A \ (B \ C)⊂(A \ B)∪C
  5. Hypotheses: none
    Conclusion: A \ (B∩C) = (A \ B)∪(A \ C)
  6. Hypotheses: none
    Conclusion: A∩(B∪C)⊂(A∩B)∪C
  7. Hypotheses: none
    Conclusion: (A∪B) \ C⊂A∪(B \ C)
  8. Hypotheses: A∩(B \ C) = ∅
    Conclusion: A∩B⊂C
  9. Hypotheses: A⊂B, A⊄C
    Conclusion: B⊄C
  10. Hypotheses: A⊂B, A∲C = ∅
    Conclusion: A⊂B \ C
  11. Hypotheses: A⊂B \ C, A∅
    Conclusion: B⊄C
  12. Hypotheses: A \ B⊂ C, A⊄C
    Conclusion: A∲B∅
  13. Hypotheses: A⊂B \ C
    Conclusion: A∲C = ∅
  14. Hypotheses: none
    Conclusion: A \ C⊂(A \ B)∪(B \ C)
  15. Hypotheses: A∩C⊂B∩C, A∪C⊂B∪C
    Conclusion: A⊂B
  16. Hypotheses: none
    Conclusion: ∃!A∀B(A∪B = B)
  17. Hypotheses: none
    Conclusion: A⊂B↔℘(A)⊂℘(B)
  18. Hypotheses: none
    Conclusion: ℘(A∩B) = ℘(A)∩℘(B)
  19. Hypotheses: none
    Conclusion: ℘(A)∪℘(B)⊂℘(A∪B)
  20. Hypotheses: ℘(A)∪℘(B) = ℘(A∪B)
    Conclusion: A⊂B∨B⊂A
  21. Hypotheses: ∀x(x∈A→x⊂A)
    Conclusion: ∀x(x∈℘(A)→x⊂℘(A))
  22. Hypotheses: A∈F
    Conclusion: A⊂∪F
  23. Hypotheses: A∈F
    Conclusion: U∩∩F⊂A
  24. Hypotheses: F⊂G
    Conclusion: ∪F⊂∪G
  25. Hypotheses: F⊂G
    Conclusion: U∩∩G⊂U∩∩F
  26. Hypotheses: none
    Conclusion: ∪(F∪G) = (∪F)∪(∪G)
  27. Hypotheses: none
    Conclusion: ∪(F∲G)⊂(∪F)∲(∪G)
  28. Hypotheses: none
    Conclusion: U∩∩(F∪G) = (U∩∩F)∩(U∩∩G)
  29. Hypotheses: none
    Conclusion: A∩(∪F) = ∪{A∩X | X∈F}
  30. Hypotheses: A⊂U
    Conclusion: A∪(U∩∩F) = U∩∩{A∪X | X∈F}
  31. Hypotheses: none
    Conclusion: U \ ∪F = U∩∩{U \ X | X∈F}
  32. Hypotheses: A⊂U
    Conclusion: A \ (U∩∩F) = ∪{A \ X | X∈F}
  33. Hypotheses: none
    Conclusion: ∪F \ ∪G⊂∪(F \ G)
  34. Hypotheses: none
    Conclusion: ∪(F \ G)⊂∪F \ ∪G→∪F∩∪G⊂∪(F∩G)
  35. Hypotheses: ∀A∈F∃B∈G(A∩B∈H)
    Conclusion: (∪F)∩∩G⊂∪H
  36. Hypotheses: none
    Conclusion: F⊂℘(∪F)
  37. Hypotheses: none
    Conclusion: A = ∪℘(A)
  38. Hypotheses: none
    Conclusion: U∩∩F∈℘(U)∩∩{℘(X) | X∈F}
  39. Hypotheses: none
    Conclusion: ∪{X \ A | X∈F}⊂∪{X∈F | X⊄A}
  40. Hypotheses: none
    Conclusion: (∪F)∲(∪G) = ∅↔∀A∈F∀B∈G(A∲B = ∅)
  41. Hypotheses: none
    Conclusion: ∪{℘(X) | X∈F}⊂℘(∪F)
  42. Hypotheses: none
    Conclusion: ℘(U)∩∩{℘(X) | X∈F} = ℘(U∩∩F)
  43. Hypotheses: ∪{℘(X) | X∈F} = ℘(∪F)
    Conclusion: ∃A∈F∀B∈F(B⊂A)
  44. Hypotheses: ∀F(∪F = A→A∈F)
    Conclusion: ∃x(A = {x})
  45. Hypotheses: none
    Conclusion: ℘(A \ B) \ (℘(A) \ ℘(B)) = {∅}
  46. Hypotheses: none
    Conclusion: A×(B∩C) = (A×B)∩(A×C)
  47. Hypotheses: none
    Conclusion: A×(B∪C) = (A×B)∪(A×C)
  48. Hypotheses: none
    Conclusion: (AΔB)∩C = (A∩C)Δ(B∩C)
  49. Hypotheses: AΔB⊂B
    Conclusion: A⊂B
  50. Hypotheses: none
    Conclusion: AΔB⊂(AΔC)∪(BΔC)
  51. Hypotheses: none
    Conclusion: AΔ(A∲B) = A \ B
  52. Hypotheses: none
    Conclusion: AΔ(A∪B) = B \ A
  53. Hypotheses: none
    Conclusion: (AΔB)ΔC = AΔ(BΔC)
  54. Hypotheses: none
    Conclusion: AΔA = ∅
  55. Hypotheses: AΔC = BΔC
    Conclusion: A = B
  56. Hypotheses: none
    Conclusion: ∃!A∀B(AΔB = B)
  57. Hypotheses: none
    Conclusion: ∀A∀B∃!C(AΔC = B)
  58. Hypotheses: none
    Conclusion: ¬∃U∀A(A∈U)
  59. Hypotheses: none
    Conclusion: (R°S)-1 = S-1°R-1
  60. Hypotheses: none
    Conclusion: (R°S)°T = R°(S°T)
  61. Hypotheses: S⊂T
    Conclusion: R°S⊂R°T
  62. Hypotheses: none
    Conclusion: (S∲T)°R⊂(S°R)∲(T°R)
  63. Hypotheses: none
    Conclusion: (S∪T)°R = (S°R)∪(T°R)
  64. Hypotheses: none
    Conclusion: (S°R) \ (T°R)⊂(S \ T)°R